Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Tai | 2246 | 109 | 1 | 109.0000 |
nes | 2076 | 90 | 1 | 90.0000 |
tačiau | 1725 | 79 | 1 | 79.0000 |
Bet | 1035 | 66 | 1 | 66.0000 |
kad | 15228 | 494 | 9 | 54.8889 |
jog | 1296 | 54 | 1 | 54.0000 |
kurie | 2050 | 115 | 3 | 38.3333 |
o | 5099 | 147 | 4 | 36.7500 |
Iš | 808 | 30 | 1 | 30.0000 |
Ši | 340 | 29 | 1 | 29.0000 |
Kaip | 1158 | 77 | 3 | 25.6667 |
Ne | 307 | 18 | 1 | 18.0000 |
Man | 269 | 17 | 1 | 17.0000 |
kuris | 1385 | 68 | 4 | 17.0000 |
Jei | 1130 | 60 | 4 | 15.0000 |
Parlamento | 250 | 15 | 1 | 15.0000 |
kurioje | 506 | 29 | 2 | 14.5000 |
Su | 248 | 14 | 1 | 14.0000 |
Pagal | 286 | 13 | 1 | 13.0000 |
kuri | 1199 | 61 | 5 | 12.2000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
proc | 448 | 1 | 53 | 0.0189 |
tūkst | 307 | 1 | 29 | 0.0345 |
val | 314 | 1 | 27 | 0.0370 |
d | 169 | 1 | 23 | 0.0435 |
mln | 367 | 2 | 32 | 0.0625 |
mėn | 131 | 1 | 14 | 0.0714 |
dr | 292 | 1 | 12 | 0.0833 |
manau | 219 | 1 | 11 | 0.0909 |
grupių | 147 | 1 | 11 | 0.0909 |
mokyklos | 221 | 1 | 11 | 0.0909 |
mlrd | 180 | 1 | 11 | 0.0909 |
Nr | 123 | 1 | 11 | 0.0909 |
Mykolo | 311 | 1 | 10 | 0.1000 |
šiek | 241 | 1 | 10 | 0.1000 |
vadovo | 106 | 1 | 10 | 0.1000 |
sistemų | 139 | 1 | 10 | 0.1000 |
teigimu | 230 | 1 | 10 | 0.1000 |
procese | 101 | 1 | 9 | 0.1111 |
klasės | 94 | 1 | 9 | 0.1111 |
sukurta | 130 | 1 | 9 | 0.1111 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II